幂函数导数及其求导过程 Posted on 2020-01-18 Edited on 2024-04-10 In 知识点 Views: Disqus: Word count in article: 214 Reading time ≈ 1 mins. 先说结论$$f\prime(x)=ax^{a-1}$$ 推导过程先对$f(x)=x^a$两边取对数$$\ln f(x)=a\ln x \(\ln f(x))\prime=\frac{1}{f(x)}f\prime(x)=\frac{a}{x} \\implies f\prime(x)=ax^{a-1}$$其中$(ln x)\prime=\frac{1}{x}$的推导参见: